Harlan township is located in Shelby County, Iowa Iowa. Unfortunately, the data for this location is currently limited or unavailable.
The median household income in Harlan township is $60,278 with a poverty rate of 8.33%. The median age in Harlan township is 41 years: 41.2 years for males, and 38.9 years for females. For every 100 females there are 102.0 males.
No data available.
Overall: 41 years
Female: 38.9 years
Male: 41.2 years
There are 623 adults, (117 of whom are seniors) in Harlan township.
Female: 392 (49.5%)
Male: 400 (50.5%)
The racial composition of Harlan township includes 97.98% White, and smaller percentages for Two or more races, Black or African American, Native American and multiracial populations.
Race | Population | Percentage (of total) |
|---|---|---|
| White | 776 | 97.98% |
| Two or more races | 8 | 1.01% |
| Black or African American | 5 | 0.63% |
| Native American | 3 | 0.38% |
Harlan township's average per capita income is $50,341. Household income levels show a median of $60,278. The poverty rate stands at 8.33%.
Name | Median | Mean |
|---|---|---|
| Married Families | $107,500 | - |
| Families | $94,219 | $105,996 |
| Households | $60,278 | $84,785 |
| Non Families | $27,969 | $39,075 |
Average Income
Median Household Income
Poverty Rate